We discovered a way to inject data trough the passphrase property of the gnupg.GPG.encrypt() and gnupg.GPG.decrypt() methods when symmetric encryption is used.
The supplied passphrase is not validated for newlines, and the library passes
--passphrase-fd=0
to the gpg executable, which expects the passphrase on the
first line of stdin, and the ciphertext to be decrypted or plaintext to be
encrypted on sebsequent lines.
By supplying a passphrase containing a newline an attacker can control/modify the ciphertext/plaintext being decrypted/encrypted.
python-gnupg 0.4.3, and maybe earlier versions
Users should upgrade to 0.4.4
- 2019-01-19: Vulnerability discovered during Insomni'hack teaser 2019
- 2019-01-20: PoC created
- 2019-01-22: Applied for CVE, Vendor notified
- 2019-01-23: CVE-2019-6690 assigned
- 2019-01-23: Vendor responded, fix committed
- 2019-01-24: Vendor released 0.4.4
- https://pypi.org/project/python-gnupg/
- https://cve.mitre.org/cgi-bin/cvename.cgi?name=CVE-2019-6690
- https://github.com/hackeriet/CVE-2019-6690-python-gnupg-vulnerability
- https://ctftime.org/task/7458
Hypothetical application using sucessful decryption of data to authenticate a user, and a way to exploit it is available here:
https://github.com/hackeriet/CVE-2019-6690-python-gnupg-vulnerability
Debian: apt install libmojolicious-perl python3-gnupg python3-flask
Nix: nix-shell
./server.py
./exploit.pl
Vulnerability discovered by Alexander Kjäll and Stig Palmquist.
Thanks to remmer.